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`""_(92)U""^(235)` nucleus absorbes a neutron and disintegrate into `""_(54)Xe""^(139),""_(38)Sr""^(94)`, and x neutrons x is
A. 3-neutrons
B. 2-neutrons
C. `alpha`particle
D. `beta`particle

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Correct Answer - A
`_(92)U^(256)` nucleus absorbs a neutron and then disntegratein `_(54)Xe^(139),_(38)Sr^(94)` and X.
Thus
`_(92U^(235)+_(0)n^(1)rarr_(54)Xe^(139)+_(38)Sr^(94)+3_(0)n^(1))`
Hence the product is 3 neutrons.

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