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A compound contains `C=40%,O=53.5%`, and `H=6.5%` the empirical formula formula of the compound is:
A. `CH_(2)O`
B. `CHO`
C. `CH_(4)O_(2)`
D. `C_(2)H_(2)O`

1 Answer

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by (91.2k points)
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Best answer
Correct Answer - A
image
Hence , empirical formula is
`C : H : O = 1: 2 : 1 = CH_(2)O`

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