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The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy `6 eV` fall on it is `4 eV` . The stopping potential , in v

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The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy `6 eV` fall on it is `4 eV` . The stopping potential , in volt is
A. 2
B. 4
C. 6
D. 10
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Correct Answer - B
`K_("max") = hv - phi rArr V_(s) = (K_(max))/(e) = (4eV)/(e) = 4` volts
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