Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
247 views
in Mathematics by (25.6k points)

If a function f defined by

f(x) = \(\begin{cases} \frac{k\,cosx}{\pi-2x}& ,if\,x≠\frac{\pi}{2}\\ 3 &, if\,x=\frac{\pi}{2}\end{cases}\) 

is continuous at x = π/2, then the value of k is :

{kcosx/(π-2x), if x ≠ π/2 3, if x = π/2

(a) 2

(b) 3

(c) 6

(d) -6

Please log in or register to answer this question.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...