Question

Electrolysis of dilute aqueous NaCl solution was carried out by passing 10 milli ampere current. The time required to liberate 0.01 mol of `H_(2)` gas at the cathode is (1 Faraday=96500 C `"mol"^(-1)`)
A. `9.65xx10^(4)` sec
B. `19.3xx10^(4)` sec
C. `28.95xx10^(4)` sec
D. `38.6xx10^(4)` sec

Answer 1

Correct Answer - B
Mass of 0.01 mol `H_(2)=0.02 g`
`W=(ItE)/(96500)`
`0.02=(10xx10^(-3) xxtxx1)/(96500)`
`t=19.3 xx 10^(4)` sec