Question

Observe the following reaction:
`A(g) + 3B(g) rarr 2C(g)`
The rate of this reaction `{(-d[A])/(d t)}` is `3 xx 10^(-3) "mol litre"^(-1) "min"^(-1)`. What is the value of `(-d[B])/(d t)` in mol `"litre"^(-1) "min"^(-1)` ?
A. `3xx10^(-3)`
B. `9xx10^(-3)`
C. `10^(-3)`
D. `1.5xx10^(-3)`

Answer 1

`(-d[A])/(dt)=-(1)/(3)(d[B])/(dt)`
`:. (-d[B])/(dt)=3{(-d[A])/(dt)}=3xx3xx10^(-3)`
`9xx10^(-3) "mol litre"^(-1) "mon"^(-1)`