First refraction from lens
`u=-40`
`(1)/(v)-(1)/(u)=(1)/(f)`
Then `v=+40 cm`.
`I_(1)` will be set as object for convex mirror
Then `v=+25 f=10 cm v=?`
`(1)/(v)+(1)/(25)=(1)/(10)`
`v=(50)/(3)`
Then refraction by lens :
`u=-(15+(50)/(3))=-(95)/(3) cm`
`(1)/(v)-(1)/(u)=(1)/(f)`
`(1)/(v)+(3)/(95)=(1)/(20)`
`v=(20xx95)/(35)`
`v=54/28 cm`
Final image will be left of lens at `54.28 cm` .