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A glass prothole is made at the botton of a ahip for observing sea life. The hole diameter `D` is much larger than the thickness of the glass. Determine the area `S` of the field of vision at the sea botton for the porthole of the refractive index of water is `mu_(w)` and the sea depth is `h`.

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Correct Answer - `pi[(h)/(sqrt(mu_(w)^(2)-1))+(D)/(2)]^(2)`
For `T.I.R sin I =(1)/(mu_(w))`
`rArr tani =(1)/(sqrt(mu_(w)^(2)-1))=(x)/(h)`
`rArr x = (h)/(sqrt(mu_(w)^(2)-1))`
Hence required area `s=pi(x+(D)/(2))^(2)`
`=pi[(h)/(sqrt(mu_(w)^(2))-1)+(D)/(2)]^(2)`
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