Question

Find the `pH` of (a)`10^(-3)M HNO_(3)` solution (b)`10^(-4)MH_(2)SO_(4)` solution (Take`log2=0.3`)

Answer 1

`(a)p-log [H^(+)]_(HNO_(3))=-log(10^(-3))=3`
`(b) pH=-log[H^(+)]_(H_(2)SO_(4))=-log(2xx10^(-4))=4-log2=3.7`
In both solution,`[H^(+)]_("from strong acid") gt 10^(-6)M` so `H^(+)` from water has not been considered.