Question

A buffer solution made up of `BOH` of total maturity `0.29M` has `pH=9.6` and `K_(b)=1.8xx10^(-5)`.Concentration of salt and base respectively is :
A. `0.09M and 0.2M`
B. `0.2 M and 0.09M`
C. `0.1 M and `0.19m`
D. `0.19M and 0.1M`

Answer 1

`pOH=-logK_(b)+log((["Salt"])/(["Base"]))`
Let a mol litre^(-1) be concentratoion of base =`(0.29-a)mol//L`
`4.4=-log1.8xx10^(-5)+log((a)/((0.29-a)))`
`:.a=0.09`
`["Salt"]=0.9M`
& `[Base]=0.29-0.09=0.20M`