Question

Area of the triangle formed by the line `x+y=3` and the angle bisectors of the pairs of straight lines `x^2-y^2+2y=1` is `2s qdotu n i t s` (b) `4s qdotu n i t s` `6s qdotu n i t s` (d) `8s qdotu n i t s`
A. 2 sq . Units
B. 4 sq . Units
C. 6 sq. units
D. 8 sq. units

Answer 1

Correct Answer - 1
`x^(2)-y^(2)+2y=1orx=+-(y-1)`

The bisectors of the above lines are `x=0 and y=1`.

So , the area between `x=0,y=1, and x+y=3` is the shaded region shown in the figure . The area is given by `(1//2)xx2xx2=2` sq. units.