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The number `N = 6 log_(10) 2+ log_(10) 31 ` lies between two successive integers whose sum is equal to

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The number `N = 6 log_(10) 2+ log_(10) 31 ` lies between two successive integers whose sum is equal to
A. 5
B. 7
C. 9
D. 10
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Correct Answer - B
`N = log_(10) 64+log_(10) 31 = log_(10) 1984`.Therefore,
` 3 lt N lt 4 rArr 7`
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