Question

`4^(log_9 3)+9^(log_2 4)=1 0^(log_x 83)`, then x is equal to
A. 2
B. 3
C. 10
D. 30

Answer 1

Correct Answer - C
`(4)^(log_(9)3)+(9)^(log_(2)4)=(10)^(log_(x)83)`
` or (4)^(1/2log_(3)3)+(9)^(2log_(2)2)=(10)^(log_(x)83)`
`or 2+81 = (10)^(log_(x) 83)`
`or 83 = (10)^(log_(x) 83)`
` rArr x = 10`