(I )From the given figure, we can analy se the chlorine atom is at the centre of the cube i.e., at equal distance from all the eight coerners of cube where cesium atoms are placed. Thus due to symmetry the forces due to all Cs tons, on Cl atom will cancel out.
Hence, `E=(F)/(q)` where F=0
`thereforeE=0`
(ii) Thus, net force on Cla atom at A would be:
where r=distance between Cl ion and Cs ion.
Applying Pythagorous theorem we get
`r=sqrt((0.20)^(2)+(0.20)^(2)+(0.20)^(2))xx10^(-9)m`
`=0.346xx10^(9)m`
Now, `F=(q^(2))/(4piepsi_(0)r^(2))=(e^(2))/(4piepsi_(0)r_(2))`
`=(9xx10^(9)(1.6xx10^(-19))^(2))/((0.346xx10^(-9))^(2))=1.92xx10^(-9)N`