Question

40 of a mixture of 0.2 mole of N₂ and 0.6 mole of H₂ react to give NH₃ according to the equation: N₂(g) + 3H₂(g) ⇋ 2NH₃(g) at constant temperature and pressure. Then the ratio of the final volume to the initial volume of gases are

(A) 4 : 5 

(B) 5 : 4 

(C) 7 :10 

(D) 8 : 5

Answer 1

Correct option (A) 4 : 5 

Explanation : 

.'. number of moles of N₂ remaining = 0.2 - 0.8 = 0.12

number of moles of H₂ remaining = 0.6 = 0.24 = 0.36

number of moles of NH₃ formed = 0.16

Total number of moles = 0.12 + 0.36 + 0.16 = 0.64