In `Delta OMP, sin theta=(3)/(5)` so MP=3 and OP=5
`because OM=sqrt((5)^(2)-(3)^(2))=sqrt(25-9)=sqrt(!6)=4`
Now, `cos theta=(OM)/(OP)=(4)/(5) tan theta =(MP)/(OM)=(3)/(4)`
`cot theta=(OM)/(MP)=(4)/(3) sec theta=(OP)/(OM)=(5)/(4) cosec theta=(OP)/(MP)=(5)/(3)`
![image](https://learnqa.s3.ap-south-1.amazonaws.com/images/16127555651275921260UoioH9QIxTXUnTpt.png)