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At STP , the density of `C Cl_(4)` vapour in g/L will be nearest to
A. 6.87
B. 3.42
C. 10.26
D. 4.57

1 Answer

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Best answer
Correct Answer - A
1 mole `C Cl_(4)` vapours `=12+4xx35.5=154 g`
At STP , volume of 1 mole of a gas =22.4 L
Thus , 154 g= 22. 4 L
`:.` Density of `C Cl_(4)` vapours `=(154)/(22.4)g L^(-1)`
`=6.87 g L ^(-1)`

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