Question

The length and breadth of a rectangle are `( 5.7 +- 0.1 ) cm and ( 3.4 +- 0.2 ) cm`, respectively calculate the area of rectangle with error limits.

Answer 1

Given `l=(5.7+00.1)cm` and `b=(3.4+-.02)m`
Area `A=lxxb=5.7xx3.4=19.38cm^(2)`
`(DeltaA)/(A)=+-((Deltal)/(l)+(Deltab)/(b))=+-((0.1)/(5.7)+(0.2)/(3.4))=+-((0.34+1.14)/(5.7xx3.4))=+-(1.48)/(19.38)`
or `DeltaA=+-(1.48)/(19.38)xxA=+-(1.48)/(19.38)xx19.8=+-148therefore "Area"=(19.38+-1.48)` sQue. cm