Question

The external and internal diameters of a hollow cylinder are measured to be `(4.23+-0.01)` cm and `(3.89+-0.01)`cm. The thickness of the wall of the cylinder is
A. `(0.34+-0.02)cm`
B. `(0.17+-0.02)cm`
C. `(0.17+-0.01)cm`
D. `(0.34+-0.01)cm`

Answer 1

Thickness of cylinder can be written as
`t=t6-Deltat`
`t=r_(2)-r_(1)=4.23-3.89=0.34`
`Deltat=Deltar_(1)+Deltar_(2)=.01+.01=.02`
`t=(0.34+-0.02)cm`