Question

The work done during the expanision of a gas from a volume of `4 dm^(3)` to `6 dm^(3)` against a constant external pressure of 3 atm is (1 L atm = 101.32 J)
A. `-6 J`
B. `-608 J`
C. `+304 J`
D. `-304 J`

Answer 1

Correct Answer - B
Work done (W) `=-P_("ext") (V_(2)-V_(1))`
`=-3xx(6-4)=-6 L atm`
`=-6xx101.32` J
`(because` 1 L atm =101.32 J`)`
`=-607.92 ~~-608 J`