Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
4.0k views
in Physics by (80.8k points)
closed by
The fig. shows the displacement time graph of a particle moving on a straight line path. What is the magnitude of average velocity of the particle over 10 seconds?
image
A. `2 ms^(-1)`
B. `4ms^(-1)`
C. `6ms^(-1)`
D. `8ms^(-1)`

1 Answer

0 votes
by (81.1k points)
selected by
 
Best answer
Correct Answer - A
Displacement=Final position-initial position
`=40-60=-20m`
`|vecv_(avg)|=(|"Displacement"|)/("time")=(20)/(10)=2m//s`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...