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Number of possible isomer for the complex `[Co(en)_(2)CI_(2)]CI` will be: (em = ethylenediamine)

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Number of possible isomer for the complex `[Co(en)_(2)CI_(2)]CI` will be: (em = ethylenediamine)
A. 2
B. 1
C. 3
D. 4
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Correct Answer - C
`[Co(en)_2Cl_2]Cl`
Possible isomers are
image
Hence, total number of stereoisomers = 2 + 1 = 3
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