Question

If a projectile is fired at an angle `theta` with the vertical with velocity u, then maximum height attained is given by:-
A. `(u^(2)cos theta)/(2g)`
B. `(u^(2)sin^(2)theta)/(2g)`
C. `(u^(2)sin^(@)theta)/(g)`
D. `(u^(2)cos^(2)theta)/(2g)`

Answer 1

Correct Answer - D
`H=(u_(y)^(2))/(2g)=(u^(2)cos^(2)theta)/(2g)`