Question

Density of ice is `rho` and that of water is `sigma`. What will be the decrease in volume when a mass `M` of ice melts?
A. `(M)/(sigma-rho)`
B. `(sigma-rho)/(M)`
C. `M[(1)/(rho)-(1)/(sigma)]`
D. `(1)/(M)[(1)/(rho)-(1)/(sigma)]`

Answer 1

Correct Answer - C
Volume of ice =`(M)/(rho)`, volume of water =`(M)/(sigma)`
`therefore "Change in volume" =(M)/(rho)-(m)/(sigma)=M((1)/(rho)-(1)/(sigma))`