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in Chemistry by (82.0k points)
Isopropylbenzene can be prepared by :
A. Benzene `+CH_(3)CH=CH_(2)overset(H_(2)SO_(4))rarr`
B. Benzene `+CH_(3)-underset(Cl)underset(|)(CH)-CH_(3)overset(H_(2)SO_(4))rarr`
C. Benzene `+CH_(3)underset(Cl)underset(|)CH-CH_(3)overset(AlCl_(3))rarr`
D. Benzene `+CH_(3)CH_(2)CH_(2)Clunderset(Delta)overset(AlCl_(3))rarr`

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