Question

Shows rod `PQ` of mass `m` and resistance `r` moving on two fixed, resistanceless, smooth conducting rails (closed on both sides by resistances `R_(1) and R_(2)`). Find the current in the rod (at the instant its velocity is `v`).

Answer 1

`i=((BlV)/(R_(1)R_(2)))/(R_(1)+R_(2))`
this circuit is equivalent to the following diagram.