Question

A compound [A] with molecular formula `C_(4)H_(10)O` reacts rapidly with metallic sodium but very slowly with Lucas reagent. When [A] treated with hot concentrated `H_(2)SO_(4)`, it gives a compound [B] `C_(4)H_(8)` which upon hydration with aqueous `H_(2)SO_(4)` forms a compound [C] with molecular formula `C_(4)H_(10)O`. The compound [C] is almost unert to metallic sodium but reacts rapidly with Lucas reagent. What are the compounds [A], [B] and [C] ? Explain the reaction involved.

Answer 1

Correct Answer - `{:((CH_(3))_(2)CHCH_(2)OH;,(CH_(3))_(2)C=CH_(2);,(CH_(3))_(3)COH),(A,B,C):}`