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A copmpound X with seven carbon atoms on treatment with `Br_(2)` and KOH gives Y, Y gives carbylamine test and upon diazotisation and coupling gives azodye, X is :
A. `C_(6)H_(5)CONH_(2)`
B. `CH_(3)-(CH_(2))_(5)-CONH_(2)`
C. `CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(2)-CH_(2)-CONH_(2)`
D. `CH_(3)-O-C_(6)H_(4)NH_(2)`

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Since Y gives coupling reaction after diazotization, it suggest that Y can be anline or benzene ring subsitututed anline, Since Y has been obtained from Hofmann bromamide it means it has `-CONH_(2)` group with benzene ring. Hence, it is `C_(6)H_(5)CONH_(2)`. Hence (A) is the correct answer

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