The voltage of an `AC` source varies with time according to the equation,`V=100 sin 100 pi I cos 100 pi t`.Where `t` is in second and `V` is in volt.Then:
A. the peak voltage of the source is `100` volt
B. the peak voltage of the source is `(100//2)` volt
C. the peak voltage of the source is `50` volt
D. the peak voltage of the source is `50 Hz`