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The equation of a wave on a string of linear mass density `0.04 kg m^(-1)` is given by `y = 0.02 (m) sin [2pi((t)/(0.04(s))-(x)/(0.50(m)))]`. The tension in the string is :
A. `4.0 N`
B. `12.5 N`
C. `0.5 N`
D. `6.25 N`

1 Answer

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Best answer
Correct Answer - 4
By equation
`f = (1)/(0.04)` and `lambda = 0.5`
`rArr V = (1)/(0.04) xx 0.5 = (25)/(2)`
by `V = sqrt((T)/(mu)) rArr ((25)/(2))^(2) = (T)/(0.04) rArr T = (625)/(4) xx 0.04`
`T = 6.25 N`

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