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Using the van der Waals equation, calculate the pressure of `10.0mol NH_(3)` gas in a `10.0 L` vessel at `27^(@)C`.
`{:((P+n^(2)(a)/(V^(2)))(V-nb)=nRT,,a=4.2L^(2).atm//mol^(2),,b=0.037L//mol):}`

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Correct Answer - `21.37atm`.
`(P+(n^(2)+4.2)/((10)^(2)) (V-nb) =nRT`
`(P+((10)^(2)xx4.2)/((10)^(2))) (10-10 xx 0.037) = 10 xx 0.082 xx 300`

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