Question

Calculate molecular diameter for a gas if its molar exclued volume is `3.2 pi ml`. (in nenometer) (Take `N_(A) = 6.0 xx 10^(23))`

Answer 1

Correct Answer - 2
`4N(4)/(3)pir^(3) = 3.2 xx pi xx 10^(-3)`
`4 xx 6 xx 10^(23) xx (4)/(3) pir^(3) = 3.2 pir^(3) = 3.2 pi xx 10^(-3)`
`r^(3) = 10^(-9)m`
`r = 1 nm` ltbr. `d = 2r = 2nm`