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Latent heat of vaporisation of water is `540cal` `g^(-1)` at `100^(@)C` calculate the entropy change when 1000 g water is converted to steam at `100^(@)C`
A. 1447 cal
B. 2447 cal
C. 3447 cal
D. 4447 cal

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Correct Answer - A
`DeltaS_(vap)=(DeltaH_(vap))/(T)=(540xx1000)/(373)=1447cal`

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