Question

Enthalpy of fusion of water is 6.01 kJ `mol^(-1)`. The entropy change of 1 mole of ice at its melting point will be:
A. 22kJ `mol^(-1)`
B. 109 kJ `mol^(-1)`
C. 44 kJ `mol^(-1)`
D. 11 kJ `mol^(-1)`

Answer 1

Correct Answer - A
`DeltaS_(fusion)=(DeltaH_(fusion))/(T_(mp))=(6.01xx1000)/(273)=22kJ` `mol^(-1)`.