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For the homogeneous reactions:
`xA+yBtolY+mZ`
`DeltaH=-30kJ" "mol^(-1),DeltaS=-100JK^(-1)" "mol^(-1)`
At what temperature the reaction is at equilibrium?
A. `50^(@)C`
B. `250^(@)C`
C. `100K`
D. `27^(@)C`

1 Answer

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Best answer
Correct Answer - D
`DeltaG=DeltaH-TDeltaS`
At equilibrium `DeltaG=0`
`thereforeT=(DeltaH)/(DeltaS)=(-30xx1000)/(-100)=300K,` i.e., `27^(@)C`.

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