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Find the quantum of the excited state of electrons in `He^(+)` ion which on transition to first excited state emit photons of wavelengths `108.5 nm`. `(R_(H)=1.09678xx10^(7) m^(-1))`
A. `6`
B. `5`
C. `4`
D. `2`

1 Answer

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Best answer
Correct Answer - B
`1/lambda=R_(H)Z^(2)[1/1^(2)-1/n_(2)^(2)]`
`1/(108.5xx10^(-9))=1.09678xx10^(7)xx4[1/2^(2)-1/n_(2)^(2)]`
This gives `n_(2)=5`

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