Question

The specific heat at constant volume for a gas is 0.075 cal/g and at constant pressure it is 0.125 cal/g. Calculate,
(i) the molecular weight of gas,
(ii). Atomicity of gas.

Answer 1

(i) `C_(P)-C_(V)=(R)/(M)` where, M=molecular of gas
`0.125-0.075=(1.987)/(M)`
`M=39.74~~40`
(ii) `(C_(P))/(C_(V))=gamma`
`therefore=(0.125)/(0.075)=1.66`
`therefore` 1.66 value of `gamma` shows that the gas is monoatomic.