Correct Answer - D
From thermodynamics we know,
ln `Kj=-(DeltaH^(@))/(RT)+(DeltaS^(@))/(R)`
`log_(10)K=-(DeltaH^(@))/(2.303R)((1)/(T))+(DeltaS^(@))/(2.303R)`
This equation shows straight line:
slope=`-(DeltaH^(@))/(2.303R)=` positive for exothermic reaction
intercept `=(DeltaS^(@))/(2.303R)`
the correct lines in the graph should be A and B.