Question

Calculate the mass of lime `(CaO)` obtained by heating `200kg` of `95%` pure lime stone `(CaCo_3)`:

Answer 1

Amount of pure of `CaCO_(3)=(95)/(100)xx200=190kg`
=190000g
`CaCO_(3)(s)toCaO(s)+CO_(2)(g)`
`"1 mole" CaCO_(3)="1 mole CaO"`
`100g CaCO_(3)=56gCaO`
`therefore 100g CaCO_(3)="give 56g CaO"`
`therefore 190000 g CaCO_(3) "will give"(56)/(100)xx190000 gCaO`
=106400g=106.4kg