Question

`2` moles of ideal gas is expanded isothermally & reversibly from `1` litre to `10` litre. Find the enthalpy changes in `KJ mol^(-1)`.

Answer 1

Correct Answer - A
` because H=E+PV` and `Delta H=Delta E+PDelta V`
`:. Delta H=Delta E +nRDelta T`
For isotermal and reversible process
`Delta T=0`
`:. Delta H=Delta E+0` ,brgt `because Delta E=0`
`because Delta H` is also equal to zero.