Correct Answer - D
In isolated system, the expansion of gas is carried out adiabatically. Since heat exchange between system and surrounding is not possible i.e. `q=0` and secondary `w_(rev)` is always greater than `w_(irr)` therefore for reversible process there must be comparatively higher decreases in internal energy i.e., `Delta U` for reversible process will be more negative. Hence, final temperature is reversible process will be smaller than irreversible process.
`:. (T_(f))_(irrev) gt(T_(f))_(rev)`