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in Mathematics by (76.4k points)

The equation of a circle passing through (1, 1) and points of intersection of x2 + y2 + 13x – 3y = 0 and 2x2 + 2y2 + 4x – 7y – 25 = 0 is 

(1) 4x2 + 4y2 – 30x – 10y – 25 = 0 

(2) 4x2 + 4y2 + 30x – 13y – 25 = 0

(3) 4x2 + 4y2 – 17x – 10y + 25 = 0 

(4) None of these

1 Answer

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Best answer

(2) 4x2 + 4y2 + 30x – 13y – 25 = 0

Explanation

The required equation of circle is

=> 4x2 + 4y2 + 30x – 13y – 25 = 0

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