Question

The accompanying diagram represents a reversible cannot cycle for an ideal gas:

What is the entropy increase during isothermal at 1000K?
A. `0.15 KJ^(-1)`
B. `150 KJ K^(-1)`
C. `150 JK^(-1)`
D. `750 JK^(-1)`

Answer 1

Correct Answer - C
`DeltaS=(q_("rev"))/(T) = (q_(h))/(T_(h)) = (150 xx 10^(3))/(1000) = 150 JK^(-1)`