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Evaluate `lim_(xtooo) (sinx)/(x).`

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We have `underset(xtooo)lim(sinx)/(x)`
Since infinity is not a fixed number, when `xtooo,sin(oo)` takes any value betwwn -1 to 1, which is finite. So, we have finite value divided by infinity. So, ratio approaches to zero.
`:." "underset(xtooo)lim(sinx)/(x)=0`

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