Question

`Cu^(+) + e^(-) rightarrow Cu`, `E^(@) = x_1volt`,
`Cu^(2+) + 2e^(-) rightarrow Cu`, `E^(@) = x_(2)` volt, then for
`Cu^(2+) + e^(-) rightarrow Cu^(+), E^(@)` (volt) will be :
A. `x_(1)-2x_(2)`
B. `x_(1)+2x_(2)`
C. `x_(1)-x_(2)`
D. `2x_(2)-x_(1)`

Answer 1

Correct Answer - D
`Cu^(+)+e^(-)toCu,E^(+)+x_(1)"volt"`
`Cu^(2+)+2e^(-)toCu,x_(2)"volt"`
`CutoCu^(+)+e^(-)-x_(1)"volt"`
`Cu^(2+)+e^(-)toCu^(+)`
`-2xx x_(2) xx f+1xx x_(1)xx f=-1xxE^(@)xxf`
`E^(@)=2x_(2)-x_(1)`