Question

The molar conductivity of a 1.5 M solution of an electrolyte is found to be `138.9 S cm^(2) mol^(-1)` . Calculate the conductivity of this solution.

Answer 1

`^^_(m)=(1000K)/(M)impliesK=(^^_(m)xxM)/(1000)=(138.9xx1.5)/(1000)=(208.35)/(1000)=(208.35)/(1000)=2.0835xx10^(-1)Scm^(-1)`