Question

A certain current liberated 0.504 g of hydrogen in 2 hours. How many gram of copper can be liberated by the same current flowing for the same time in `CuSO_(4)` solution ?
A. 31.8 g
B. 16.0 g
C. 12.7 g
D. 63.5 g

Answer 1

Correct Answer - C
`(W_(1))/(E_(1))=(W_(2))/(E_(2))`
`(W_(Cu))/((63.5)/(2))=(0.504)/((2)/(2))`
`W_(Cu)=0.504xx63.5=31.8gm`.