Question

How much mass (kg) of `CaCO_(3)` is needed to produce 336 kg of Cao ? [Given : % yield of reaction = 60]
A. `10^(3)`
B. `10^(2)`
C. 900
D. 800

Answer 1

Correct Answer - A
`CaCO_(3)(s)rarrunderset(336kg)(CaO(s))+CO_(2)1g`
Moles of CaO = `(336)/(56)xx10^(3)=6xx10^(3)`
Mass of `CaCO_(3)` required `=6xx10^(3)xx(100)/(60)xx100=10^(3)kg`