Question

Find the equation of the line perpendicular to the line `x/a-y/b=1` and passing through a point at which it cuts the x-axis.

Answer 1

Correct Answer - `(x)/(b) + (y)/(a) = (a)/(b)`
The given line is
bx-ay=ab
Obviously, it cuts the x-axis at (a,0).
The equation of line perpendicular to above line is
ax+by=k
But it passes through (a,0). Therefore,
`k=a^(2)`
Hence, the required equation of line is
`ax+by =a^(2)`
`i.e., (x)/(b)+(y)/(a) = (a)/(b)`