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A straight line through the point `(2,2)` intersects the lines `sqrt(3)x+y=0` and `sqrt(3)x-y=0` at the point `A` and `B ,` respectively. Then find th

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A straight line through the point `(2,2)` intersects the lines `sqrt(3)x+y=0` and `sqrt(3)x-y=0` at the point `A` and `B ,` respectively. Then find the equation of the line `A B` so that triangle `O A B` is equilateral.
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Correct Answer - y-2=0
`sqrt(3)x+y=0 " makes an angle of " 120^(@) " with OX, whereas"`
`sqrt(3)x-y=0 " makes an angle of " 60^(@) " with OX. Therefore, the required line is " y-2=0.`
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